How To Accelerate Weight Loss
Physical: Weight Loss apparent problem. (Newton's Laws)?
A woman of 65 kg down briefly in an elevator that is accelerating at .20 g to to exit a low floor. He stands on a scale that reads in kg. (A) During acceleration, which is their weight and what the scale read? (B) what is the dose scale reading when the elevator descends 2.0 m / s? —- Could you please include the procedure on how to complete this problem. In addition, for (A) are: mg-Fn = m (20 g) and then solve for Fn, which is equal to 0.80 mg Why? Thank you very much. I do not understand how the mg-.2mg = 0.8 mg. Why does mg = 1?
scale records and displays the normal force acting on the Newton's second law is the sum of forces = ma in this case, the sum of forces are the normal force, and the weight of the person acting downward, these combine to produce the acceleration of 0.2 g-Therefore, Newton's second law becomes: Sum of forces = N – mg = ma N – mg = m (-0.2g) =- 0.2 mg N = mg = 0.8 mg 0.2 mg-scale was recorded 80% of their weight (or mass), or 52 kg b) if the elevator moves at constant speed, either up or down, there is no acceleration and measurement of normal-weight scale
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